document.write( "Question 483103: The diameters of grapefruits in a certain orchard are normally distributed with a mean of 5.93 inches and a standard deviation of 0.59 inches. Show all work.
\n" ); document.write( "(A) What percentage of the grapefruits in this orchard is larger than 5.88 inches?
\n" ); document.write( "(B) A random sample of 100 grapefruits is gathered and the mean diameter is calculated. What is the probability that the sample mean is greater than 5.88 inches?
\n" ); document.write( " Thanks much
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Algebra.Com's Answer #330625 by stanbon(75887)\"\" \"About 
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The diameters of grapefruits in a certain orchard are normally distributed with a mean of 5.93 inches and a standard deviation of 0.59 inches. Show all work.
\n" ); document.write( "(A) What percentage of the grapefruits in this orchard is larger than 5.88 inches?
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\n" ); document.write( "z(5.88) = (5.88-5.93)/0.59 = -0.0847
\n" ); document.write( "P(x > 5.88) = P(z > -0.0847) = 0.5338
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\n" ); document.write( "(B) A random sample of 100 grapefruits is gathered and the mean diameter is calculated. What is the probability that the sample mean is greater than 5.88 inches?
\n" ); document.write( "z(5.88) = (5.88-5.93)/[0.59/sqrt(100)] = -0.8475
\n" ); document.write( "P(x-bar > 5.88) = P(z > -0.8475) = 0.8016
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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