document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483077>Question 483077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Iam not in understanding of the substitution method can someone please help?\r<BR>\n" );
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document.write( "4x+6y=16<BR>\n" );
document.write( "6x +y =3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330608 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Iam not in understanding of the substitution method can someone please help? <BR>\n" );
document.write( "4x+6y=16<BR>\n" );
document.write( "6x +y =3<BR>\n" );
document.write( "**<BR>\n" );
document.write( "Solve for y in the second equation<BR>\n" );
document.write( "y=3-6x<BR>\n" );
document.write( "sub 3-6x for y in first equation<BR>\n" );
document.write( "4x+6(3-6x)=16<BR>\n" );
document.write( "4x+18-36x=16<BR>\n" );
document.write( "-32x=-2<BR>\n" );
document.write( "x=2/32=1/16 </SPAN>\n" );
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