document.write( "Question 483077: Iam not in understanding of the substitution method can someone please help?\r
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\n" ); document.write( "\n" ); document.write( "4x+6y=16
\n" ); document.write( "6x +y =3
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Algebra.Com's Answer #330607 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"4%2Ax%2B6%2Ay=16\"
\n" ); document.write( " \"6%2Ax%2B1%2Ay=3\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"6%2Ay=16-4%2Ax\"Subtract \"4%2Ax\" from both sides
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\n" ); document.write( " \"y=%2816-4%2Ax%29%2F6\" Divide both sides by 6.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=8%2F3-%282%2F3%29%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"8%2F3-%282%2F3%29%2Ax\" we can substitute the expression \"8%2F3-%282%2F3%29%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"6%2Ax%2B1%2Ahighlight%28%288%2F3-%282%2F3%29%2Ax%29%29=3\" Replace y with \"8%2F3-%282%2F3%29%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"6%2Ax%2B1%2A%288%2F3%29%2B1%28-2%2F3%29x=3\" Distribute 1 to \"8%2F3-%282%2F3%29%2Ax\"
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\n" ); document.write( " \"6%2Ax%2B8%2F3-%282%2F3%29%2Ax=3\" Multiply
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\n" ); document.write( " \"6%2Ax%2B8%2F3-%282%2F3%29%2Ax=3\" Reduce any fractions
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\n" ); document.write( " \"6%2Ax-%282%2F3%29%2Ax=3-8%2F3\" Subtract \"8%2F3\" from both sides
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\n" ); document.write( " \"6%2Ax-%282%2F3%29%2Ax=9%2F3-8%2F3\" Make 3 into a fraction with a denominator of 3
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\n" ); document.write( " \"6%2Ax-%282%2F3%29%2Ax=1%2F3\" Combine the terms on the right side
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\n" ); document.write( " \"%2818%2F3%29%2Ax-%282%2F3%29x=1%2F3\" Make 6 into a fraction with a denominator of 3
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\n" ); document.write( " \"%2816%2F3%29%2Ax=1%2F3\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%283%2F16%29%2816%2F3%29%29x=%281%2F3%29%283%2F16%29\" Multiply both sides by \"3%2F16\". This will cancel out \"16%2F3\" and isolate x
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\n" ); document.write( " So when we multiply \"1%2F3\" and \"3%2F16\" (and simplify) we get
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\n" ); document.write( " \"x=1%2F16\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=1%2F16\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"6%281%2F16%29%2B1%2Ay=3\" Plug in \"x=1%2F16\" into the 2nd equation
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\n" ); document.write( " \"3%2F8%2B1%2Ay=3\" Multiply
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\n" ); document.write( " \"1%2Ay=3-3%2F8\"Subtract \"3%2F8\" from both sides
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\n" ); document.write( " \"1%2Ay=24%2F8-3%2F8\" Make 3 into a fraction with a denominator of 8
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\n" ); document.write( " \"1%2Ay=21%2F8\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ay=%2821%2F8%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out 1 on the left side.
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\n" ); document.write( " \"y=21%2F8\" Multiply the terms on the right side
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\n" ); document.write( " \"y=21%2F8\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=21%2F8\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=1%2F16\" and \"y=21%2F8\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"1%2F16\",\"21%2F8\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"4%2Ax%2B6%2Ay=16\"
\n" ); document.write( " \"6%2Ax%2B1%2Ay=3\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"4%2Ax%2B6%2Ay=16\" (red) and \"6%2Ax%2B1%2Ay=3\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"1%2F16\",\"21%2F8\"). This verifies our answer.
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\n" ); document.write( " Check:
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\n" ); document.write( " Plug in (\"1%2F16\",\"21%2F8\") into the system of equations
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\n" ); document.write( " Let \"x=1%2F16\" and \"y=21%2F8\". Now plug those values into the equation \"4%2Ax%2B6%2Ay=16\"
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\n" ); document.write( " \"4%2A%281%2F16%29%2B6%2A%2821%2F8%29=16\" Plug in \"x=1%2F16\" and \"y=21%2F8\"
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\n" ); document.write( " \"4%2F16%2B126%2F8=16\" Multiply
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\n" ); document.write( " \"256%2F16=16\" Add
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\n" ); document.write( " \"16=16\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"1%2F16\",\"21%2F8\") satisfies \"4%2Ax%2B6%2Ay=16\"
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\n" ); document.write( " Let \"x=1%2F16\" and \"y=21%2F8\". Now plug those values into the equation \"6%2Ax%2B1%2Ay=3\"
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\n" ); document.write( " \"6%2A%281%2F16%29%2B1%2A%2821%2F8%29=3\" Plug in \"x=1%2F16\" and \"y=21%2F8\"
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\n" ); document.write( " \"6%2F16%2B21%2F8=3\" Multiply
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\n" ); document.write( " \"48%2F16=3\" Add
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\n" ); document.write( " \"3=3\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"1%2F16\",\"21%2F8\") satisfies \"6%2Ax%2B1%2Ay=3\"
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\n" ); document.write( " Since the solution (\"1%2F16\",\"21%2F8\") satisfies the system of equations
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\n" ); document.write( " \"4%2Ax%2B6%2Ay=16\"
\n" ); document.write( " \"6%2Ax%2B1%2Ay=3\"
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\n" ); document.write( " this verifies our answer.
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