document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483070>Question 483070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The substitution method has my head twisted can someone help me please???\r<BR>\n" );
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document.write( "-2y+ 6x=50 <BR>\n" );
document.write( "2y-11x=66 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330603 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The substitution method has my head twisted can someone help me please??? <BR>\n" );
document.write( "-2y+ 6x=50 <BR>\n" );
document.write( "2y-11x=66<BR>\n" );
document.write( "**<BR>\n" );
document.write( "solve for 2y in first equation<BR>\n" );
document.write( "2y=6x-50<BR>\n" );
document.write( "sub 2y into second equation<BR>\n" );
document.write( "6x-50-11x=66<BR>\n" );
document.write( "-5x=116<BR>\n" );
document.write( "x=-116/5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );