document.write( "Question 49776: Please solve the equation and be sure to check your solution.
\n" ); document.write( "sqrt of 4x+1+3=0
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Algebra.Com's Answer #33049 by tutorcecilia(2152) $\"\"$ $\"About$

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$\"%28sqrt+%284x%2B1%29%29%2B3=0%29\"$
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\n" ); document.write( " $\"%28sqrt+%284x%2B1%29%29%2B3-3=0-3%29\"$
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\n" ); document.write( " $\"%28sqrt+%284x%2B1%29%29=-3%29\"$
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\n" ); document.write( " $\"%28sqrt+%284x%2B1%29%29%5E2=%28-3%29%5E2\"$
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\n" ); document.write( "4x+1=9
\n" ); document.write( "4x+1-9=9-9
\n" ); document.write( "4x+1-9=0
\n" ); document.write( "4x-8=0
\n" ); document.write( "4x-8+8=0+8
\n" ); document.write( "4x/4=8/4
\n" ); document.write( "x=2
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\n" ); document.write( "check by plugging x=2 back into the original equation. Remember that the square root is \"plus\" or \"minus\" a number, so try both. \n" ); document.write( "

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