document.write( "Question 482907: Please Help me: Household income does not tend to follow a normal distribution in a particular state, yet average income is approximately $45,000/year in this state, with a standard deviation of about $9000. Approximately what percentage of household incomes in this state is between $27,000 to $63,000/year? Show all work as to how this is obtained. \n" ); document.write( "
Algebra.Com's Answer #330489 by stanbon(75887) ![]() You can put this solution on YOUR website! Household income does not tend to follow a normal distribution in a particular state, yet average income is approximately $45,000/year in this state, with a standard deviation of about $9000. Approximately what percentage of household incomes in this state is between $27,000 to $63,000/year? Show all work as to how this is obtained. \n" ); document.write( "-------------------------- \n" ); document.write( "(27000-45000)/9000 = -2 \n" ); document.write( "--- \n" ); document.write( "(63000-45000)/9000 = 2 \n" ); document.write( "----- \n" ); document.write( "Using Chebychev's approximation, (1-(1/2)^2)% = 0.75% of the \n" ); document.write( "households will fall in that range. \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |