document.write( "Question 49777: Please solve the equation and check your solution.
\n" ); document.write( "sqrt of 2y+7+4=y
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Algebra.Com's Answer #33048 by tutorcecilia(2152)\"\" \"About 
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\"%28+%28%28sqrt%282y%2B7%29%29+%2B+4%29%29+=+y%29%29%29%29+\"
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\n" ); document.write( "\"%28+%28%28sqrt%282y%2B7%29%29+%2B+4+-+4%29%29+=+y+-+4%29%29%29%29+\" [Isolate the radical to one side]
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\n" ); document.write( "\"%28+%28%28sqrt%282y%2B7%29%29%29%29+=+y+-+4%29%29%29%29+\"
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\n" ); document.write( "\"%28+%28%28%28sqrt%282y%2B7%29%29%29%29%29%5E2+=+%28%28y+-+4%29%29%5E2%29%29%29%29+\" [Square both sides]
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\n" ); document.write( "2y+7 = (y - 4)(y - 4) [Multiply by using the FOIL method]
\n" ); document.write( "2y+7=y^2-8y+16[Set the equaion equal to zero by getting all of the terms to one side of the equation]
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\n" ); document.write( "2y+7-7=y^2-7-8y+16
\n" ); document.write( "2y=y^2-8y+9
\n" ); document.write( "2y-2y=y^2-8y-2y+9
\n" ); document.write( "0=y^2-10y+9 [Factor]
\n" ); document.write( "0 = (y-9)(y-1) [solve for y]
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\n" ); document.write( "0=y-9
\n" ); document.write( "y=9
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\n" ); document.write( "0=y-1
\n" ); document.write( "y=1
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\n" ); document.write( "y=9 or y=1 [Final answers]
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\n" ); document.write( "Check by plugging the values of \"y\" back into the original equatin.\r
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