document.write( "Question 49777: Please solve the equation and check your solution.
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document.write( "sqrt of 2y+7+4=y \n" );
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Algebra.Com's Answer #33048 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "2y+7 = (y - 4)(y - 4) [Multiply by using the FOIL method] \n" ); document.write( "2y+7=y^2-8y+16[Set the equaion equal to zero by getting all of the terms to one side of the equation] \n" ); document.write( ". \n" ); document.write( "2y+7-7=y^2-7-8y+16 \n" ); document.write( "2y=y^2-8y+9 \n" ); document.write( "2y-2y=y^2-8y-2y+9 \n" ); document.write( "0=y^2-10y+9 [Factor] \n" ); document.write( "0 = (y-9)(y-1) [solve for y] \n" ); document.write( ". \n" ); document.write( "0=y-9 \n" ); document.write( "y=9 \n" ); document.write( ". \n" ); document.write( "0=y-1 \n" ); document.write( "y=1 \n" ); document.write( ". \n" ); document.write( "y=9 or y=1 [Final answers] \n" ); document.write( ". \n" ); document.write( "Check by plugging the values of \"y\" back into the original equatin.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |