document.write( "Question 482801: what is the equation to solving this kind of problem? \r
\n" ); document.write( "\n" ); document.write( "At 1:00 PM Lucia left her home and began walking at 6 km/hr toward Kiley’s house. Fifteen minutes later, Kiley left her home and walked at 9 km/hr toward Lucia’s house. If Lucia lives 5 km from Kiley, at what time did they meet? Who walked farther?
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Algebra.Com's Answer #330461 by jorel1380(3719)\"\" \"About 
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6k per hour x 1/4 hour=1.5 k's
\n" ); document.write( "5-1.5=3.5
\n" ); document.write( "9n+6n=3.5
\n" ); document.write( "15n=3.5
\n" ); document.write( "n=.2333 hours
\n" ); document.write( "Lucia walked 1.5+.233333(6)=2.9 k's
\n" ); document.write( "Kiley walked .2333333(9)=2.1 k's
\n" ); document.write( "Lucia walked further..
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