document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=482564>Question 482564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to find the square root of i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330436 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330436\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE i = e^{i\frac{\pi}{2}} = \cos(\frac{\pi}{2}) + i*\sin(\frac{\pi}{2})\"> (I know this uses a circular definition but you can still find the square root of i this way)\r<BR>\n" );
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document.write( "Take square root of both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \sqrt{i} = \sqrt{e^{i\frac{\pi}{2}}} = e^{i\frac{\pi}{4}} = \cos(\frac{\pi}{4}) + i \sin(\frac{\pi}{4}) = \frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2}i\">\r<BR>\n" );
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document.write( "Similar to real numbers, there can be a negative square root (e.g. sqrt(9) being equal to -3 as well as 3), but these roots are usually ignored. </SPAN>\n" );
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