document.write( "Question 482509: a trough is formed by nailing together, edge to edge, two boards 11 ft. in length, so that the right section is a right triangle. If 15 gal. of water are poured into the trough ad if the trough is held level so that a right section of the water is an isosceles right triangle, how deep is the water? (231 cu. in. = 1 gal.) \n" ); document.write( "
Algebra.Com's Answer #330434 by ankor@dixie-net.com(22740)\"\" \"About 
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a trough is formed by nailing together, edge to edge, two boards 11 ft. in length, so that the right section is a right triangle.
\n" ); document.write( " If 15 gal. of water are poured into the trough ad if the trough is held level so that a right section of the water is an isosceles right triangle, how deep is the water? (231 cu. in. = 1 gal.)
\n" ); document.write( ":
\n" ); document.write( "Find the vol of the water in cu/in
\n" ); document.write( "15 * 231 = 3465 cu/in
\n" ); document.write( ":
\n" ); document.write( "Change 11 ft: 11*12 = 132 inches
\n" ); document.write( ":
\n" ); document.write( "Find the triangular area of the end of the trough; 3465/132 = 26.25 sq/inches
\n" ); document.write( ":
\n" ); document.write( "Let x = width of the trough; A right triangle area =
\n" ); document.write( "\"1%2F2\"x*x = 26.25
\n" ); document.write( "x^2 = 2(26.25)
\n" ); document.write( "x = \"sqrt%2852.5%29\"
\n" ); document.write( "x = 7.2457 inches the width of each board
\n" ); document.write( ";
\n" ); document.write( "Find the width of the trough which is the the hypotenuse
\n" ); document.write( "h = \"sqrt%28x%5E2+%2B+x%5E2%29\"
\n" ); document.write( "h = \"sqrt%2852.5+%2B+52.5%29\"
\n" ); document.write( "h = \"sqrt%28105%29\"
\n" ); document.write( "h = 10.247 inches wide, also the base of the triangle
\n" ); document.write( ":
\n" ); document.write( "Find the altitude of the triangle, which is the depth of the water; we know it's area
\n" ); document.write( "\"1%2F2\"*10.247*d = 26.25
\n" ); document.write( "10.247d = 2(26.25)
\n" ); document.write( "10.247d = 52.5
\n" ); document.write( "d = \"52.5%2F10.247\"
\n" ); document.write( "d = 5.12 inches is the depth of the water
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the vol of water with these measurements
\n" ); document.write( "\"1%2F2\"*10.247*5.12*132 = 3462.366 cu/inches which is about 15 gal
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