document.write( "Question 482779: 4over7+5over4-1over2 \n" ); document.write( "
Algebra.Com's Answer #330424 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The / works well for over (except for radio commo) \n" ); document.write( " \n" ); document.write( "The 3 terms have to have the same denominator to be combined, called \"common denominator\" The product of the denominators (regardless of the # of terms) always works. 7*4*2 = 56. But for this one, it's easy to spot that 2 is a factor of 4, and use 7*4 instead. \n" ); document.write( "--------------------- \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( " \n" ); document.write( " |