document.write( "Question 482742: If 53% of college applications were submitted online, and I have a sample of 1000 apps., with 530 submitted online, how do I solve this question if I use a significance level of 0.01. Do the apps. equal 50%\r
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document.write( "I know how to state the clain and find the null and alternative hypothesis. I am having problems actually setting up the problem. \n" );
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Algebra.Com's Answer #330412 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If 53% of college applications were submitted online, and I have a sample of 1000 apps., with 530 submitted online, how do I solve this question if I use a significance level of 0.01. Do the apps. equal 50% \n" ); document.write( "---- \n" ); document.write( "Ho: p = 0.50 (claim) \n" ); document.write( "H1: p is not equal to 0.50 \n" ); document.write( "---------------- \n" ); document.write( "Sample proportion: 530/1000 = 0.530 \n" ); document.write( "test statistic: \n" ); document.write( "z(0.53) = (0.53-0.50)/sqrt[0.5*0.5/sqrt(530)] = 0.2879 \n" ); document.write( "--- \n" ); document.write( "p-value = 2*P(z > 0.2879) = 0.7734 \n" ); document.write( "--- \n" ); document.write( "Since the p-value is greater than 1%, fail to reject Ho. \n" ); document.write( "The test results support the claim. \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " \n" ); document.write( " |