document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49774>Question 49774</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a perfect circle inscribed inside of a perfect square where the sides of the square are tangent to the circle. In one corner of the square is a rectangle that ia 140mm x 70mm. The rectangle is perfectly squared in the corner and the bottom corner just touches the outside of the circle. \r<BR>\n" );
document.write( "\n" );
document.write( "What is the diameter of the circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33041 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have a perfect circle inscribed inside of a perfect square where the sides of the square are tangent to the circle. In one corner of the square is a rectangle that ia 140mm x 70mm. The rectangle is perfectly squared in the corner and the bottom corner just touches the outside of the circle. <BR>\n" );
document.write( "What is the diameter of the circle?\r<BR>\n" );
document.write( "\n" );
document.write( "GOOD PROBLEM.TRY TO TO DRAW A FIGURE AS DESCRIBED BELOW FOR BETTER UNDERSTANDING<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28600%2C600%2C-400%2C400%2C-400%2C400%2Cred%28+line%28+-350%2C0%2C350%2C0+%29%0D%0A%29%2Clocate%28+0%2C+0%2C+C+%29%2Cred%28+line%28+0%2C-350%2C0%2C350+%29+%29%2Clocate%28%0D%0A350%2C350%2CR+%29%2Clocate%28+350%2C280%2C+Q+%29%2Cred%28+line%28+-350%2C350%2C-350%2C-350+%29%0D%0A%29%2Clocate%28+210%2C280%2CP+%29%2Cgreen%28circle%280%2C0%2C350%29%29%2Clocate%28+0%2C+350%2C%0D%0AT%29%2Clocate%280%2C280%2Cx%29%2Cred%28line%28350%2C280%2C0%2C280%29%29%2Cred%28line%28210%2C280%2C210%2C350%29%29%2Cred%28line%280%2C0%2C210%2C280%29%29%2Clocate%28210%2C350%2CS%29%2Cred%28line%28350%2C-350%2C350%2C350%29%29%2Cred%28line%28350%2C350%2C-350%2C350%29%29%2Cred%28line%28-350%2C350%2C-350%2C350%29%29%2Cred%28line%28-350%2C-350%2C350%2C-350%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "LET THE CENTRE OF CIRCULAR PIZZA BE 'C'.THIS IS SAME AS THE CENTRE OF THE BOX.LET THE CARD BE PQRS..LET IT TOUCH THE CIRCULAR PIZZA AT P.JOIN OP<BR>\n" );
document.write( "OP IS THE RADIUS=R SAY TO BE FOUND.WE HAVE..<BR>\n" );
document.write( "PQ=RS=140....  <BR>\n" );
document.write( "PS=QR=70...GIVEN<BR>\n" );
document.write( "DRAW CT FROM CENTRE C A RADIUS PERPENDICULAR TO RS.<BR>\n" );
document.write( "EXTEND QP TO MEET CT AT X.<BR>\n" );
document.write( "WE HAVE CT=RADIUS=R=CP<BR>\n" );
document.write( "PSTX IS A RECTANGLE.<BR>\n" );
document.write( "PS=70=XT<BR>\n" );
document.write( "PX=QPX-QP=R-140<BR>\n" );
document.write( "CX=CXT-XT=R-70.<BR>\n" );
document.write( "NOW IN THE RIGHT ANGLED TRIANGLE CPX,WE HAVE <BR>\n" );
document.write( "CP=R=HYPOTENUSE<BR>\n" );
document.write( "CX=ONE SIDE=R-70<BR>\n" );
document.write( "PX=ANOTHER SIDE=R-140<BR>\n" );
document.write( "USING PYTHOGARUS THEOREM ,WE HAVE....HYPOTENUSE^2=SIDE^2+SIDE^2<BR>\n" );
document.write( "R^2=(R-70)^2+(R-140)^2<BR>\n" );
document.write( "R^2=R^2-140R+4900+R^2-280R+19600<BR>\n" );
document.write( "R^2-420R+24500=0<BR>\n" );
document.write( "R^2-70R-350R+24500=0<BR>\n" );
document.write( "R(R-70)-350(R-70)=0<BR>\n" );
document.write( "(R-70)(R-350)=0<BR>\n" );
document.write( "R-70=0.....OR....R=70....NOT POSSIBLE AS THEN IT TOUCHES THE LOWER EDGE OVERLAPPING THE PIZZA.<BR>\n" );
document.write( "R-350=0......R=350 IS THE ANSWER.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );