document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=482623>Question 482623</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the digits of a two digit number is 15.if the number formed by reversing the digits is less than the original number by 27.find the original number<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330404 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the tens digit be T, and the units digit U\r<BR>\n" );
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document.write( "As sum of digits = 15, then T + U = 15\r<BR>\n" );
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document.write( "The value of this number is: 10(T) + U. or 10T + U, and when reversed, we have: 10(U) + T, or 10U + T\r<BR>\n" );
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document.write( "Since the # formed by reversing the digits is 27 less than the original number, then we can say that:\r<BR>\n" );
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document.write( "10U + T = 10T + U – 27 -------->  – 9T + 9U = -27\r<BR>\n" );
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document.write( "We now have the following simultaneous equations:\r<BR>\n" );
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document.write( "    T +   U = 15 _____ (i) <BR>\n" );
document.write( "– 9T + 9U = - 27 _____ (ii)<BR>\n" );
document.write( "9T + 9U = 135 _______ (iii) ----- Multiplying eq (i) by 9<BR>\n" );
document.write( "18U = 108 _______ Adding eq (ii) and eq (iii)\r<BR>\n" );
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document.write( "U, or the units digit = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=108%2F18 ALIGN=MIDDLE  ALT=\"108%2F18\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%286%29 ALIGN=MIDDLE  ALT=\"highlight%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Substituting 6 for U in eq (i), we get: T + 6 = 15 ----- T, or the tens digit = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%289%29 ALIGN=MIDDLE  ALT=\"highlight%289%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now, since the tens digit is 9, and the units digit is 6, this makes the number: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2896%29 ALIGN=MIDDLE  ALT=\"highlight_green%2896%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Check<BR>\n" );
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document.write( "When 96 (original #) is reversed, it becomes 69. 69 is in fact 27 less than 96 (96 - 69 = 27).\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to MathMadEzy@aol.com </SPAN>\n" );
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