document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=482696>Question 482696</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On Jerry's way to work in the morning, he was only able to travel at a rate of 20 mph because of traffic. On his drive home, he averaged 40mph. If his total time was 1 1/2 hours, how long did it take him to drive to work? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330384 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I would set this up in the following manner with two equations:<BR>\n" );
document.write( "rate*time = rate*rime\r<BR>\n" );
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document.write( "20x = 40y<BR>\n" );
document.write( "x + y = 1.5; <BR>\n" );
document.write( "y = 1.5 - x\r<BR>\n" );
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document.write( "Then substitute equation two into equation one.<BR>\n" );
document.write( "20x =  40(1.5- x)<BR>\n" );
document.write( "20x = 60 - 40x<BR>\n" );
document.write( "60x = 60<BR>\n" );
document.write( "x = 1<BR>\n" );
document.write( "y therefore comes out to .5<BR>\n" );
document.write( "Cleomenius.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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