document.write( "Question 482516: what is x in the equation 3x squared + 2x =0 \n" ); document.write( "
Algebra.Com's Answer #330313 by LagrangeSon678(5)\"\" \"About 
You can put this solution on YOUR website!
This problem can be solved by factoring:\r
\n" ); document.write( "\n" ); document.write( "more specifically by factoring out a common term.\r
\n" ); document.write( "\n" ); document.write( "In this case: 3x^2+2x=0, we can factor out an x, since it is common to both 3x^2 and 2x.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This results in: x(3x+2)=0.\r
\n" ); document.write( "\n" ); document.write( "Now we simply set each term to equal zero like so:\r
\n" ); document.write( "\n" ); document.write( "x=0\r
\n" ); document.write( "\n" ); document.write( "3x+2=0\r
\n" ); document.write( "\n" ); document.write( "Now solve for x,\r
\n" ); document.write( "\n" ); document.write( "Oviously, x=0, thats on solution\r
\n" ); document.write( "\n" ); document.write( "The second solution comes from 3x+2=0. First subtract 2 from both sides, giving us 3x=-2. Then divide both sides by 3, resulting in x=-2/3.\r
\n" ); document.write( "\n" ); document.write( "Our solution are :\r
\n" ); document.write( "\n" ); document.write( "x=0 and x=-2/3\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );