document.write( "Question 482461: can somebody help me solve this problem and show me the work so i understand how to do it\r
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Algebra.Com's Answer #330281 by Edwin McCravy(20056)\"\" \"About 
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document.write( "5-2(x+6)=1\r\n" );
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document.write( "We copy down the 5 under that\r\n" );
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document.write( "5-2(x+6)=1\r\n" );
document.write( "5\r\n" );
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document.write( "Now we multiply the -2 by the x and get -2x and write that down\r\n" );
document.write( "after the 5:\r\n" );
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document.write( "5-2(x+6)=1\r\n" );
document.write( "5-2x\r\n" );
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document.write( "Now we multiply the -2 by the +6 and get -12 and write that down\r\n" );
document.write( "after the 5-2x:\r\n" );
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document.write( "5-2(x+6) = 1\r\n" );
document.write( "5-2x-12\r\n" );
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document.write( "Now we bring down the equal sign and the 1:\r\n" );
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document.write( "5-2(x+6) = 1\r\n" );
document.write( "5-2x-12  = 1\r\n" );
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document.write( "Now on the next line we combine the 5 and the -12 getting -7 and \r\n" );
document.write( "write that on the next line without the 5 and the -12, but we \r\n" );
document.write( "bring down the -2x, the = sign and the 1 and we have\r\n" );
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document.write( "5-2(x+6) = 1\r\n" );
document.write( "5-2x-12  = 1\r\n" );
document.write( "  -7-2x  = 1\r\n" );
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document.write( "Next we add 7 to both sides canceling the -7 on the left and giving\r\n" );
document.write( "8 on the right, and we bring down only the -2x, the = and the 1 to the \r\n" );
document.write( "next line:\r\n" );
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document.write( "5-2(x+6) = 1\r\n" );
document.write( "5-2x-12  = 1\r\n" );
document.write( "  -7-2x  = 1\r\n" );
document.write( "    -2x  = 8\r\n" );
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document.write( "Finally we divide both sides by -2, getting x on the left and -4 on\r\n" );
document.write( "the right, and we put that on the bottom line.\r\n" );
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document.write( "5-2(x+6) = 1\r\n" );
document.write( "5-2x-12  = 1\r\n" );
document.write( "  -7-2x  = 1\r\n" );
document.write( "    -2x  = 8\r\n" );
document.write( "      x  = -4 \r\n" );
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document.write( "Edwin

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