document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=482426>Question 482426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, thanks so so much for helping me out!!!  I am working on substitution and am really confused!  here is my problem\r<BR>\n" );
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document.write( "-5x+3y=12<BR>\n" );
document.write( "  x+2y=8\r<BR>\n" );
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document.write( "I Tried:<BR>\n" );
document.write( "-5x+3y=12<BR>\n" );
document.write( "  x+2y=8<BR>\n" );
document.write( "(-5)+2y=8<BR>\n" );
document.write( " +5    +5            But then I was told I need 2 answers and I don't know how<BR>\n" );
document.write( "    2y= 13              to find the second answer!<BR>\n" );
document.write( "      13/2<BR>\n" );
document.write( "     y =6.5<BR>\n" );
document.write( "  <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #330267 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=330267\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I set the second equation up as x = -2y + 8\r<BR>\n" );
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document.write( "Then substituted into the first equation:<BR>\n" );
document.write( "-5(-2y + 8) + 3y = 12<BR>\n" );
document.write( "10y -40 + 3y = 12<BR>\n" );
document.write( "13y = 52<BR>\n" );
document.write( "y = 4\r<BR>\n" );
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document.write( "into first equation:<BR>\n" );
document.write( "-5x + 12 = 12 , x = 0<BR>\n" );
document.write( "into second equation <BR>\n" );
document.write( "0 + 2(4) = 8.<BR>\n" );
document.write( "Cleomenius. </SPAN>\n" );
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