document.write( "Question 482426: Hi, thanks so so much for helping me out!!! I am working on substitution and am really confused! here is my problem\r
\n" ); document.write( "\n" ); document.write( "-5x+3y=12
\n" ); document.write( " x+2y=8\r
\n" ); document.write( "\n" ); document.write( "I Tried:
\n" ); document.write( "-5x+3y=12
\n" ); document.write( " x+2y=8
\n" ); document.write( "(-5)+2y=8
\n" ); document.write( " +5 +5 But then I was told I need 2 answers and I don't know how
\n" ); document.write( " 2y= 13 to find the second answer!
\n" ); document.write( " 13/2
\n" ); document.write( " y =6.5
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #330266 by rfer(16322)\"\" \"About 
You can put this solution on YOUR website!
x+2y=8
\n" ); document.write( "change to
\n" ); document.write( "x=-2y+8
\n" ); document.write( "------------
\n" ); document.write( "-5x+3y=12
\n" ); document.write( "-5(-2y+8)+3y=12
\n" ); document.write( "10y-40+3y=12
\n" ); document.write( "13y=52
\n" ); document.write( "y=4
\n" ); document.write( "------------------
\n" ); document.write( "-5x+3*4=12
\n" ); document.write( "-5x+12=12
\n" ); document.write( "-5x=12-12
\n" ); document.write( "x=0
\n" ); document.write( "---------------
\n" ); document.write( "x+2y=8
\n" ); document.write( "0+2*4=8
\n" ); document.write( "-----------------
\n" ); document.write( "Does that help?
\n" ); document.write( "Bob
\n" ); document.write( "
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