document.write( "Question 482426: Hi, thanks so so much for helping me out!!! I am working on substitution and am really confused! here is my problem\r
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document.write( "-5x+3y=12
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document.write( " x+2y=8\r
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document.write( "I Tried:
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document.write( "-5x+3y=12
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document.write( " x+2y=8
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document.write( "(-5)+2y=8
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document.write( " +5 +5 But then I was told I need 2 answers and I don't know how
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document.write( " 2y= 13 to find the second answer!
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document.write( " 13/2
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document.write( " y =6.5
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Algebra.Com's Answer #330266 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! x+2y=8 \n" ); document.write( "change to \n" ); document.write( "x=-2y+8 \n" ); document.write( "------------ \n" ); document.write( "-5x+3y=12 \n" ); document.write( "-5(-2y+8)+3y=12 \n" ); document.write( "10y-40+3y=12 \n" ); document.write( "13y=52 \n" ); document.write( "y=4 \n" ); document.write( "------------------ \n" ); document.write( "-5x+3*4=12 \n" ); document.write( "-5x+12=12 \n" ); document.write( "-5x=12-12 \n" ); document.write( "x=0 \n" ); document.write( "--------------- \n" ); document.write( "x+2y=8 \n" ); document.write( "0+2*4=8 \n" ); document.write( "----------------- \n" ); document.write( "Does that help? \n" ); document.write( "Bob \n" ); document.write( " |