document.write( "Question 481949: If stronium-90 has a half-life of fourteen days, and you have a sample that contains 30 kg of strontium-90, how much would remain after thirty-five days? \n" ); document.write( "
Algebra.Com's Answer #330236 by ankor@dixie-net.com(22740)\"\" \"About 
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If stronium-90 has a half-life of fourteen days, and you have a sample that contains 30 kg of strontium-90, how much would remain after thirty-five days?
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\n" ); document.write( "A = Ao*2^(-t/h)
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\n" ); document.write( "A = 30*2^(-35/14)
\n" ); document.write( "A = 30*2^-2.5
\n" ); document.write( "A = 30*.17678
\n" ); document.write( "A = 5.3 kg after 35 days
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