document.write( "Question 481949: If stronium-90 has a half-life of fourteen days, and you have a sample that contains 30 kg of strontium-90, how much would remain after thirty-five days? \n" ); document.write( "
Algebra.Com's Answer #330236 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If stronium-90 has a half-life of fourteen days, and you have a sample that contains 30 kg of strontium-90, how much would remain after thirty-five days? \n" ); document.write( ": \n" ); document.write( "A = Ao*2^(-t/h) \n" ); document.write( ": \n" ); document.write( "A = 30*2^(-35/14) \n" ); document.write( "A = 30*2^-2.5 \n" ); document.write( "A = 30*.17678 \n" ); document.write( "A = 5.3 kg after 35 days \n" ); document.write( " |