document.write( "Question 49749: I'm stuck. I am supposed to solve for t and the original equation is:
\n" ); document.write( "x=vt-(1/2)at^2
\n" ); document.write( "Here is what I have done so far.
\n" ); document.write( "2x=2vt-at^2
\n" ); document.write( "2x=t(2v-at)
\n" ); document.write( "t=2x/(2v-at)
\n" ); document.write( "But since I am supposed to solve for t how do I get the other t out or am I done?
\n" ); document.write( "Thanks!!
\n" ); document.write( "Andrea
\n" ); document.write( "

Algebra.Com's Answer #33017 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, your first few steps are fine. Remember, when you solve an equation for a specified variable, in this case it's t, you have to write the equation so that the variable t in on one side of the equals sign and everything else is on the other side. If you have a t on both sides of the equation, the job won't be finished. Let's pick it up where you got it right so far:\r
\n" ); document.write( "\n" ); document.write( "\"2x+=+2vt-at%5E2\" Now this begins to look much like a quadratic equation in t, so let's put it into the standard form for quadratic equations: \"at%5E2%2Bbt%2Bc+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"at%5E2-2vt%2B2x+=+0\" This is the same equation you had only it's now in the standard form. Now you can solve this quadratic equation using the quadratic formula: \"t+=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\" In your equation: a = a, b = -2v, and c = 2x\r
\n" ); document.write( "\n" ); document.write( "\"t+=+%28-%28-2v%29%2B-sqrt%28%28-2v%29%5E2+-+4%28a%29%282x%29%29%29%2F2%28a%29\" Simplify this.
\n" ); document.write( "\"t+=+%282v%2B-sqrt%284v%5E2-8ax%29%29%2F2a\"
\n" ); document.write( "\"t+=+%282v%2B-sqrt%284%28v%5E2-2ax%29%29%29%2F2a\"
\n" ); document.write( "\"t+=+%282v%2B-2sqrt%28v%5E2-2ax%29%29%2F2a\"\r
\n" ); document.write( "\n" ); document.write( "As with any quadratic equation, there are two solutions:\r
\n" ); document.write( "\n" ); document.write( "\"t+=+%28v%2Fa%29%2B%28sqrt%28v%5E2-2ax%29%29%2Fa\" and
\n" ); document.write( "\"t+=+%28v%2Fa%29-%28sqrt%28v%5E2-2ax%29%29%2Fa\"
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