document.write( "Question 482227: Chloe is 2 years older than his husband damon. if the product of their ages is 30 more than 15 times the sum of their ages. how old is chloe
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Algebra.Com's Answer #330151 by emargo19(101)![]() ![]() ![]() You can put this solution on YOUR website! Chole’s age = c \n" ); document.write( "Husband’s age = h \n" ); document.write( "Product of their ages = c*h \n" ); document.write( "Sum of their ages = c+h \n" ); document.write( "15 times the sum of their ages = 15 (c+h) \n" ); document.write( "Chole two years older than her husband so if we add 2 years to the husband’s age both will be the same age \n" ); document.write( "c=h+2 …….(1) \n" ); document.write( "the product of their ages is thirty more than fifteen times the sum of their ages \n" ); document.write( "c*h=30+15(c+h)……..(2) \n" ); document.write( "Put the value of c from (1) to (2) \n" ); document.write( "(h+2)*h=30+15[(h+2)+h] \n" ); document.write( "h^2+2h=30+15h+30+15h \n" ); document.write( "h^2+2h=60+30h \n" ); document.write( "h^2+2h-60-30h=0 \n" ); document.write( "h^2-28h-60=0 \n" ); document.write( "h^2-30h+2h-60=0 \n" ); document.write( "h(h-30)-2(h-30)=0 \n" ); document.write( "(h+2)(h-30) \n" ); document.write( "h=-2 h=30 \n" ); document.write( "h=-2 impossible \n" ); document.write( "so h=30 \n" ); document.write( "Husband is 30 years old \n" ); document.write( "And \n" ); document.write( "Chole is 32 \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |