document.write( "Question 49763This question is from textbook PreCalculus with limits agraphing approach
\n" ); document.write( ": In Exercises 43-52, find the general form of the equation of the line that passes through the points. Use a graphing utility to sketch the line
\n" ); document.write( "44.(4,3),((-4,-4) \n" ); document.write( "
Algebra.Com's Answer #33015 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
(4,3),(-4,-4) [Given points]
\n" ); document.write( "m =(y2-y1)/(x2-x1) [To find the slope, use the slope formula since two points are given]
\n" ); document.write( ".
\n" ); document.write( "m =(-4-3)(-4-4) [Plug-in the values]
\n" ); document.write( "m = -7/-8 = 7/8 [The slope of the line]
\n" ); document.write( ".
\n" ); document.write( "Ax+By=C [General Form of the equation of the line]
\n" ); document.write( "(y-y1) = m(x-x1) [Use the point-slope formula since you now have the slope and two points]
\n" ); document.write( ".
\n" ); document.write( "(y-3) = (7/8)(x-4) [Plug-in the values for the (m) and one of the points (4,3)]
\n" ); document.write( "y-3 = (7/8)x - (7/8)(4) [Simplify]
\n" ); document.write( "y-3 = (7/8)x -7/2 [Isolate all of the variables on one side of the equation]
\n" ); document.write( "y-3+3 = (7/8)x-(7/2)+3
\n" ); document.write( "y = (7/8)x-(1/2)
\n" ); document.write( "y -(7/8)x = (7/8)x-(7/8)x -(1/2)
\n" ); document.write( "y -(7/8)x = -1/2 [Re-arrange the terms]
\n" ); document.write( "-7/8x + y = -1/2 [General Form of the equation of the line][Final answer]
\n" ); document.write( ".
\n" ); document.write( "Check by plugging the values of the points back into the General Form]\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );