document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49743>Question 49743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HEY I WAS WANTING TO KNOW HOW TO SLOVE THIS LINEAR EQUATION BY SUBSTITUTION. THE PROBLEM LOOKS LIKE THIS. 4X+Y=6<BR>\n" );
document.write( "                                y=2X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33012 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33012\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SINCE Y=2X THEN SUBSTITUTING 2X FOR Y IN THE OTHER EQUATION WE GET 4X+2X=6 THEN\r<BR>\n" );
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document.write( "6X=6 OR X=1 NOW SOLVING FOR Y IN Y=2X WE GET Y=2*1 OR Y=2 </SPAN>\n" );
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