document.write( "Question 482134: A container has 20 L of a mixture of alcohol and water which is 40% alcohol by volume. How much of the mixture should be removed and replaced by an equal volume of water so that the resulting solution will be 25% alcohol by volume?
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Algebra.Com's Answer #330100 by mathstutor494(120)![]() ![]() You can put this solution on YOUR website! Current composition of mixture...... \n" ); document.write( "Alcohol : 20*40/100 = 8 L \n" ); document.write( "So water 20-8 : 12 L\r \n" ); document.write( "\n" ); document.write( "New composition of mixture required.... \n" ); document.write( "Alcohol : 20*25/100 = 5 L \n" ); document.write( "So Water : 15 L\r \n" ); document.write( "\n" ); document.write( "So mixture to be removed and replaced by an equal volume of water = 3L \n" ); document.write( " \n" ); document.write( " |