document.write( "Question 482134: A container has 20 L of a mixture of alcohol and water which is 40% alcohol by volume. How much of the mixture should be removed and replaced by an equal volume of water so that the resulting solution will be 25% alcohol by volume?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #330100 by mathstutor494(120)\"\" \"About 
You can put this solution on YOUR website!
Current composition of mixture......
\n" ); document.write( "Alcohol : 20*40/100 = 8 L
\n" ); document.write( "So water 20-8 : 12 L\r
\n" ); document.write( "\n" ); document.write( "New composition of mixture required....
\n" ); document.write( "Alcohol : 20*25/100 = 5 L
\n" ); document.write( "So Water : 15 L\r
\n" ); document.write( "\n" ); document.write( "So mixture to be removed and replaced by an equal volume of water = 3L
\n" ); document.write( "
\n" ); document.write( "
\n" );