document.write( "Question 482134: A container has 20 L of a mixture of alcohol and water which is 40% alcohol by volume. How much of the mixture should be removed and replaced by an equal volume of water so that the resulting solution will be 25% alcohol by volume?
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Algebra.Com's Answer #330097 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent percentage ---------------- quantity \n" ); document.write( "Alcohol 40 ---------------- x liters \n" ); document.write( "water 0 ---------------- 20 - x liters \n" ); document.write( "Mixture 25.00% ---------------- 20 \n" ); document.write( " \n" ); document.write( "40x+0(20-x) = 25 * 20 \n" ); document.write( " \n" ); document.write( "40 x = 500 \n" ); document.write( " \n" ); document.write( "/ 40 \n" ); document.write( " x=12.5 liters 40.00% Alcohol \n" ); document.write( " 7.5liters water \n" ); document.write( "7.5 liters of mixture has to be replaced with water \n" ); document.write( " |