document.write( "Question 482125: I know this is pretty simple but its slipped my mind, how do you solve for the product of an equations like these: (x-4)(x+3) ; (3x-2)(2x-5) ; (4x-3)(x^2+2x-5) ??? I just completely blanked on these. \n" ); document.write( "
Algebra.Com's Answer #330096 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%28x%2B3%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "Now let's FOIL the expression.\r
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\n" ); document.write( "\n" ); document.write( "Remember, when you FOIL an expression, you follow this procedure:\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%28x%29-4%29%28highlight%28x%29%2B3%29\" Multiply the First terms:\"%28x%29%2A%28x%29=x%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%28x%29-4%29%28x%2Bhighlight%283%29%29\" Multiply the Outer terms:\"%28x%29%2A%283%29=3%2Ax\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2Bhighlight%28-4%29%29%28highlight%28x%29%2B3%29\" Multiply the Inner terms:\"%28-4%29%2A%28x%29=-4%2Ax\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2Bhighlight%28-4%29%29%28x%2Bhighlight%283%29%29\" Multiply the Last terms:\"%28-4%29%2A%283%29=-12\".\r
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\n" ); document.write( "\n" ); document.write( "So we have the terms: \"x%5E2\", \"3%2Ax\", \"-4%2Ax\", \"-12\" \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3%2Ax-4%2Ax-12\" Now add every term listed above to make a single expression.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-12\" Now combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"%28x-4%29%28x%2B3%29\" FOILs to \"x%5E2-x-12\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%28x-4%29%28x%2B3%29=x%5E2-x-12\".
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