document.write( "Question 482019: A person invested $10,000. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160 more than the annual income from the smaller part. What is the smaller part of the investment? \n" ); document.write( "
Algebra.Com's Answer #330043 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! .06p=.05(10000-p)+160 \n" ); document.write( "6p=5(10000-p)+16000 \n" ); document.write( "6p=50000-5p+16000 \n" ); document.write( "11p=66000 \n" ); document.write( "p=6000 \n" ); document.write( "$6000 was invested at 6%, and $4000 was invested at 5%.. \n" ); document.write( " |