document.write( "Question 482019: A person invested $10,000. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160 more than the annual income from the smaller part. What is the smaller part of the investment? \n" ); document.write( "
Algebra.Com's Answer #330043 by jorel1380(3719)\"\" \"About 
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.06p=.05(10000-p)+160
\n" ); document.write( "6p=5(10000-p)+16000
\n" ); document.write( "6p=50000-5p+16000
\n" ); document.write( "11p=66000
\n" ); document.write( "p=6000
\n" ); document.write( "$6000 was invested at 6%, and $4000 was invested at 5%..
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