document.write( "Question 482001: (-2) to the 5th power + (-5) to the 2nd power. I get really confused on how to do these. I have tried over and over again and I still can't get the right answer. \n" ); document.write( "
Algebra.Com's Answer #330035 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+%28-2%29%5E5+%2B+%28-5%29%5E2+\"
\n" ); document.write( "You can always write these out the long way
\n" ); document.write( "( if the numbers aren't very big ) and look at them
\n" ); document.write( "\"+%28-2%29%2A%28-2%29%2A%28-2%29%2A%28-2%29%2A%28-2%29+%2B+%28-5%29%2A%28-5%29+\"
\n" ); document.write( "The main thing to notice is that there are an odd number of
\n" ); document.write( "(-2)'s and an even number of (-5)'s
\n" ); document.write( "Think of the (-2)'s grouped in pairs with one left over
\n" ); document.write( "(-2)*(-2) this is positive
\n" ); document.write( "(-2)*(-2) also positive
\n" ); document.write( "(-2) this is negative
\n" ); document.write( "So, you have (+) x (+) x (-) = (-)
\n" ); document.write( "---------------------------
\n" ); document.write( "What if it was \"+%28-2%29%5E67+\" ?
\n" ); document.write( "You would pair these up the same way, so you'd have
\n" ); document.write( "a bunch of (+) x (+) x (+) . . . etc and one (-) left. that would
\n" ); document.write( "give you a minus result
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\n" ); document.write( "Back to your problem, then
\n" ); document.write( "\"+%28-2%29%5E5+=+-32+\"
\n" ); document.write( "and
\n" ); document.write( "\"+%28-5%29%5E2+=+25+\"
\n" ); document.write( "\"+-32+%2B+25+=+-7+\"
\n" ); document.write( "OK?
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