document.write( "Question 482003: factor this polynomial completely
\n" ); document.write( " $\"3y%5E5-75y%5E3\"$ \n" ); document.write( "

Algebra.Com's Answer #330032 by kingme18(98) $\"\"$ $\"About$

You can put this solution on YOUR website!
Any time you factor a polynomial, your first step is to factor out the GCF (Greatest Common Factor). In your case, both terms are divisible by $\"3y%5E3\"$ , so we factor that out first (and divide both terms by the GCF inside the parentheses): $\"3y%5E3%28y%5E2-25%29\"$ . Now, look inside the parentheses. That's a difference of two squares, and can be factored...the rule is $\"a%5E2-b%5E2=%28a%2Bb%29%28a-b%29\"$ , so since $\"y%5E2-25=y%5E2-5%5E2\"$ , it factors to $\"%28y%2B5%29%28y-5%29\"$ . Don't forget that GCF you factored out; your final answer is $\"3y%5E3%28y%2B5%29%28y-5%29\"$ \n" ); document.write( "

\n" );