document.write( "Question 6213: x2+2x+3=0 have to solve it by fatrisation or by completing square. from new syllabus d book 3 chapter 1 ex 1c. \n" ); document.write( "

Algebra.Com's Answer #3300 by Earlsdon(6294) $\"\"$ $\"About$

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Since you are given a choice of methods, you can see (or should be able to) that \"factorisation\" won't work here so you would use \"completing the square\".\r
\n" ); document.write( "\n" ); document.write( "x^2 + 2x + 3 = 0 Subtract 3 from both sides.
\n" ); document.write( "x^2 + 2x = -3 Complete the square on the left by adding the square of half the coefficient of the x-term to both sides. (Half of 2 is 1. 1 squared is 1)\r
\n" ); document.write( "\n" ); document.write( "x^2 + 2x + 1 = -3 + 1
\n" ); document.write( "x^2 + 2x + 1 = -2 Factor the left side.
\n" ); document.write( "(x + 1)(x + 1) = -2
\n" ); document.write( "(x + 1)^2 = -2 Take the square root of both sides.
\n" ); document.write( "x+1= +/- sqrt(-2)
\n" ); document.write( "x = -1 +/- sqrt(-2)
\n" ); document.write( "x = -1 + sqrt(2)i or x = -1 - sqrt(2)i Where i = sqrt(-1) \n" ); document.write( "

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