document.write( "Question 481867: Divide and Check\r
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Algebra.Com's Answer #329919 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Divide and Check
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document.write( "(x^3+2x^2-3x+2)/(x-1) = x^2 + 3x  R = 2
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document.write( "Using Synthetic Division:
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document.write( "1	1	2	-3	2
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document.write( "		1	3	0
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document.write( "	1	3	0	2
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document.write( "Checking:
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document.write( "(x-1)(x^2+3x)+ 2(x-1)/(x-1)= x^3 + 2x^2 -3x - 2 \n" );
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