document.write( "Question 481709: (x+y)/(3a-b)=(y+z)/(3b-c)=(z+x)/(3c-a)
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document.write( "prove that
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document.write( "(x+y+z)/(a+b+c)=(ax+by+cz)/(a^2+b^2+c^2) \n" );
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Algebra.Com's Answer #329857 by mananth(16946)![]() ![]() You can put this solution on YOUR website! You have to apply the rule of identities. \n" ); document.write( " \n" ); document.write( "a1/b1 = a2/b2 = a3/b3 \n" ); document.write( "= (a1+a2+a3)/(b1+b2+b3) ---- 1 \n" ); document.write( " = (a1-a2+a3)/(b1-b2+b3) ---- 2 \n" ); document.write( " = (a2-a3+a1)/(b2-b3+b1) ---- 3 \n" ); document.write( " = (a3-a1+a2)/(b3-b1+b2) ---- 4 \n" ); document.write( ".............. \n" ); document.write( " \n" ); document.write( "apply to the given equations: \n" ); document.write( " \n" ); document.write( " = \n" ); document.write( " = \n" ); document.write( " \n" ); document.write( "= \n" ); document.write( " = \n" ); document.write( " = \n" ); document.write( " = \n" ); document.write( " \n" ); document.write( "= \n" ); document.write( " = \n" ); document.write( " = \n" ); document.write( " = \n" ); document.write( " \n" ); document.write( "= \n" ); document.write( " = \n" ); document.write( " = \n" ); document.write( " = \n" ); document.write( " \n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |