document.write( "Question 481498: Find the focus and directrix of the parabola with the given equation. Then graph the parabola.\r
\n" ); document.write( "\n" ); document.write( " y^=-12x \n" ); document.write( "

Algebra.Com's Answer #329843 by lwsshak3(11628) $\"\"$ $\"About$

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Find the focus and directrix of the parabola with the given equation. Then graph the parabola.
\n" ); document.write( "y^=-12x
\n" ); document.write( "**
\n" ); document.write( "y^2=-12x
\n" ); document.write( "This is an equation of a parabola with a horizontal axis of symmetry.
\n" ); document.write( "Its standard form: (y-k)^2=4p(x-h), with (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "For given equation:
\n" ); document.write( "Vertex(0,0)
\n" ); document.write( "4p=12
\n" ); document.write( "p=3
\n" ); document.write( "Focus:(-3,0)
\n" ); document.write( "Directrix: x=3
\n" ); document.write( "see the graph below as a visual check on the answers:
\n" ); document.write( "..
\n" ); document.write( "y=ą(-12x)^.5
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+%28-12x%29%5E.5%2C-%28-12x%29%5E.5%29+\"$ \n" ); document.write( "

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