document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=481744>Question 481744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Present age of father is 13 years more than the twice of his son. 6 years ago sum of the ages of father and son was 49 years. Find the present age of father and son. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329840 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let<BR>\n" );
document.write( "Father’s age =f<BR>\n" );
document.write( "Son’s age=s\r<BR>\n" );
document.write( "\n" );
document.write( "Father is 13 years more than twice of his son <BR>\n" );
document.write( "f=2s+13 …………..(1)<BR>\n" );
document.write( "6 years ago means subtract 6 from both ages then sum which is equal to 49<BR>\n" );
document.write( "(f-6)+(s-6)=49<BR>\n" );
document.write( "f-6+s-6=49<BR>\n" );
document.write( "f-12+s=49<BR>\n" );
document.write( "f+s=49+12 ………….(2)<BR>\n" );
document.write( "Put the value of   f  from 1 into (2)<BR>\n" );
document.write( "2s+13+s=61<BR>\n" );
document.write( "3s=61-13<BR>\n" );
document.write( "3s=48<BR>\n" );
document.write( "s=48/3<BR>\n" );
document.write( "s=16<BR>\n" );
document.write( "f=2(16)+13<BR>\n" );
document.write( "f=32+13<BR>\n" );
document.write( "f=45<BR>\n" );
document.write( "Father is 45 and son is 16 years old. <BR>\n" );
document.write( " </SPAN>\n" );
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