document.write( "Question 481738: Rational Expressions / Teachers question: For each equation, state the values of x that would result in division by zero when substituted into the original equation. show your work.\r
\n" ); document.write( "\n" ); document.write( " I will have to write it out as i cannot get the problem to look correct when I make it look like the book. so here goes\r
\n" ); document.write( "\n" ); document.write( "3 over X-9 = 1 over X squared - 9X plus 2
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\n" ); document.write( "\n" ); document.write( "3
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\n" ); document.write( "X-9
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\n" ); document.write( "X sq - 9x +2\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance =)
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Algebra.Com's Answer #329830 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Here's the problem for reference:\r
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\n" ); document.write( "\n" ); document.write( "\"3%2F%28x-9%29=1%2F%28x%5E2-9x%29%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "One thing to always remember: You CANNOT divide by zero. So something like \"1%2F0\" is undefined.\r
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\n" ); document.write( "\n" ); document.write( "So this means that the denominators \"x-9\" and \"x%5E2-9x\" CANNOT be equal to zero (to avoid division by zero)\r
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\n" ); document.write( "\n" ); document.write( "So if \"x-9=0\", then \"x=9\". This means that if x=9, then the first denominator is zero, which is not allowed.\r
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\n" ); document.write( "\n" ); document.write( "Also, if \"x%5E2-9x=0\" then \"x%28x-9%29=0\" which means that \"x=0\" or \"x=9\" when we solve for x. So if x=0 or x=9, then the second denominator will be zero, which is not allowed.\r
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\n" ); document.write( "\n" ); document.write( "So the following values of x will result in division by zero: 0, 9
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