document.write( "Question 481640: If you have 70mL of 35% solution of acid in water, how much water would you add in order to make a 25% acid solution? \n" ); document.write( "
Algebra.Com's Answer #329772 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
If you have 70mL of 35% solution of acid in water, how much water would you add in order to make a 25% acid solution?
\n" ); document.write( "------------------------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.35*70 + 0*x = 0.25(70+x)
\n" ); document.write( "----
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "35*70 + 0 = 25*70+25x
\n" ); document.write( "-----
\n" ); document.write( "25x = 10*70
\n" ); document.write( "----
\n" ); document.write( "x = 28mL (amt. of water needed)
\n" ); document.write( "=======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );