document.write( "Question 481640: If you have 70mL of 35% solution of acid in water, how much water would you add in order to make a 25% acid solution? \n" ); document.write( "
Algebra.Com's Answer #329772 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If you have 70mL of 35% solution of acid in water, how much water would you add in order to make a 25% acid solution? \n" ); document.write( "------------------------------------------ \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.35*70 + 0*x = 0.25(70+x) \n" ); document.write( "---- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "35*70 + 0 = 25*70+25x \n" ); document.write( "----- \n" ); document.write( "25x = 10*70 \n" ); document.write( "---- \n" ); document.write( "x = 28mL (amt. of water needed) \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |