document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=481576>Question 481576</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is three times another number. if the sum is 52 what are the numbers? i have tried 15 times 3=45 +7= 52 but it doesn't seem to be correct what am i doing wrong? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329740 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329740\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try this:<BR>\n" );
document.write( "Let the two numbers be a and b, then:<BR>\n" );
document.write( "a+b = 52 and<BR>\n" );
document.write( "a = 3b Substitute this for a in the first equation.<BR>\n" );
document.write( "3b+b = 52 Simplify.<BR>\n" );
document.write( "4b = 52 Divide both sides by 4.<BR>\n" );
document.write( "b = 13 and<BR>\n" );
document.write( "a = 3(13)<BR>\n" );
document.write( "a = 39<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "13+39 = 52.<BR>\n" );
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