document.write( "Question 481597: How you derived the following?\r
\n" ); document.write( "\n" ); document.write( "x+x/3+2x/3+x+x/3=150\r
\n" ); document.write( "\n" ); document.write( "(10x)/3 = 150\r
\n" ); document.write( "\n" ); document.write( "My exact question here is how do you get the 10x? thanks
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #329733 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%2Bx%2F3%2B2x%2F3%2Bx%2Bx%2F3=150\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x%2F3%2Bx%2F3%2B2x%2F3%2B3x%2F3%2Bx%2F3=150\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%283x%2Bx%2B2x%2B3x%2Bx%29%2F3=150\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%2810x%29%2F3=150\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"10x=150%2A3\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"10x=450\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=450%2F10\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=45\"
\n" ); document.write( "
\n" );