document.write( "Question 481513: What is the end behavior of f(x) = –x^3 + 2 ? \n" ); document.write( "

Algebra.Com's Answer #329697 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=-x%5E3%2B2\"$ \r
\n" ); document.write( "\n" ); document.write( "-odd-degree polynomials have ends that head off in opposite directions \r
\n" ); document.write( "\n" ); document.write( "-if they start \"down\" (entering the graphing \"box\" through the \"bottom\") and go \"up\" (leaving the graphing \"box\" through the \"top\"), they're positive polynomials; \r
\n" ); document.write( "\n" ); document.write( "-if they start \"up\" and go \"down\", they're negative polynomials\r
\n" ); document.write( "\n" ); document.write( "Since the leading coefficient of this odd-degree polynomial is negative, then its end-behavior is going to mimic a negative cubic:\r
\n" ); document.write( "\n" ); document.write( " $\"+graph%28+500%2C+500%2C+-6%2C+5%2C+-10%2C+10%2C-x%5E3%2B2%29+\"$ \n" ); document.write( "

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