document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=481392>Question 481392</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ages of a mother and a daughter are 31 years and 7 years respectively. In how <BR>\n" );
document.write( "many years  will the mother’s age be 3/2 times that of daughter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329649 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mother’s age=m=31<BR>\n" );
document.write( "Daughter’s age=d=7<BR>\n" );
document.write( " after y years mother and daughter will be<BR>\n" );
document.write( "m+y= d+y<BR>\n" );
document.write( "and the mother’s age be 3/2 times of daughter<BR>\n" );
document.write( "(m+y)= (3/2) (d+y)<BR>\n" );
document.write( "(m+y)= 3 (d+y)/2<BR>\n" );
document.write( "2(m+y)=3(d+y)<BR>\n" );
document.write( "2m+2y=3d+3y<BR>\n" );
document.write( "2m-3d=3y-2y<BR>\n" );
document.write( "y=2m-3d<BR>\n" );
document.write( "y=2(31)-3(7)<BR>\n" );
document.write( "y=62-21<BR>\n" );
document.write( "y=41<BR>\n" );
document.write( "In 41 years </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );