document.write( "Question 481369: Please help me solve this problem, thank you.\r
\n" ); document.write( "\n" ); document.write( "Which term of the arithmetic progression -7,-5,-3 . . . is 65?
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Algebra.Com's Answer #329643 by Maths68(1474)\"\" \"About 
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Tn=a+(n-1)d
\n" ); document.write( "T=term
\n" ); document.write( "n=Number of term
\n" ); document.write( "a=first term
\n" ); document.write( "d=Common difference
\n" ); document.write( "In this particular series
\n" ); document.write( "a=-7,
\n" ); document.write( "d=-5-(-7)=-5+7=2
\n" ); document.write( "Tn=65\r
\n" ); document.write( "\n" ); document.write( "Tn=a+(n-1)d
\n" ); document.write( "65=-7+(n-1)2
\n" ); document.write( "65=-7+2n-2
\n" ); document.write( "65=-9+2n
\n" ); document.write( "65-9=2n
\n" ); document.write( "54=2n
\n" ); document.write( "54/2=n
\n" ); document.write( "27=n
\n" ); document.write( "n=27
\n" ); document.write( "65 is the27 term of the series -7,-5,-3,.......65
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