document.write( "Question 481380: Identify the vertex and directrix of the parabola (x+4)^2=-1/8(y+3)\r
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document.write( "Write the equation of a parabola a directrix at x = 1 and a focus at (-3, 0).\r
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document.write( "thank you! \n" );
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Algebra.Com's Answer #329638 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Identify the vertex and directrix of the parabola (x+4)^2=-1/8(y+3) \n" ); document.write( "and Write the equation of a parabola a directrix at x = 1 and a focus at (-3, 0). \n" ); document.write( "** \n" ); document.write( "(x+4)^2=-1/8(y+3) \n" ); document.write( "This is an equation of a parabola of the standard form: (x-h)^2=-4p(y-k), with (h,k) being the coordinates of the vertex, and the parabola opens downwards. \n" ); document.write( "For given equation: \n" ); document.write( "vertex: (-4,-3) \n" ); document.write( "4p=1/8 \n" ); document.write( "p=1/32 \n" ); document.write( "directrix:y=-3+1/32) \n" ); document.write( ".. \n" ); document.write( "directrix at x = 1 and a focus at (-3, 0) \n" ); document.write( "Given data shows this is an equation of a parabola of the standard form: (y-k)^2=-4p(x-h) \n" ); document.write( "vertex: (-1,0) \n" ); document.write( "Equation: y^2=-8(x+1) \n" ); document.write( "see graph as a visual check on the answer \n" ); document.write( ".. \n" ); document.write( "y=±(-8(x+1))^.5 \n" ); document.write( " |