document.write( "Question 481381: Identify the center and the radius of the circle (x – 4)2 + (y + 3)2 = 81.\r
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document.write( "Identify the center of the ellipse x^2/3+(y+1)^2/5=1\r
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document.write( "thank you! \n" );
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Algebra.Com's Answer #329636 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Identify the center and the radius of the circle (x – 4)2 + (y + 3)2 = 81. \n" ); document.write( "and Identify the center of the ellipse x^2/3+(y+1)^2/5=1. \n" ); document.write( "** \n" ); document.write( "Standard form for equation of a circle: (x-h)^2+(y-k)^2=r^2, (h,k) being the (x,y) coordinates \n" ); document.write( "of the center. \n" ); document.write( "For given equation of circle: \n" ); document.write( "(x–4)^2+(y+3)^2=81 \n" ); document.write( "center: (4,-3) \n" ); document.write( "radius: √81=9 \n" ); document.write( ".. \n" ); document.write( "Standard form for equation of an ellipse with vertical major axis: \n" ); document.write( "(x-h)^2/b^2+(y-k)^2/a^2=1, a>b, (h,k) being the (x,y) coordinates of the center. \n" ); document.write( "For given equation of ellipse: \n" ); document.write( "x^2/3+(y+1)^2/5=1 \n" ); document.write( "center: (0,-1) \n" ); document.write( " |