document.write( "Question 481264: Three consecutive odd integers are such that the square of the second is 96 less than the square of the third. Find the three integers. \n" ); document.write( "

Algebra.Com's Answer #329552 by ccs2011(207) $\"\"$ $\"About$

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Let the 3 odd integers be n, n+2, n+4
\n" ); document.write( "Set up equation
\n" ); document.write( " $\"%28n%2B2%29%5E2+=+%28n%2B4%29%5E2+-96\"$
\n" ); document.write( " $\"n%5E2%2B4n%2B4+=+n%5E2%2B8n%2B16-96\"$
\n" ); document.write( "Combine like terms
\n" ); document.write( " $\"4n+=+84\"$
\n" ); document.write( " $\"n+=+21\"$
\n" ); document.write( "Three integers are 21,23,25 \n" ); document.write( "

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