document.write( "Question 481249: x cubed-5x=0
\n" ); document.write( "i tried to factor it out- x(x squared -5) but i dont know how I could get that to equal 0. \n" ); document.write( "
Algebra.Com's Answer #329535 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
You were correct in your approach...
\n" ); document.write( "\"x%5E3-5x+=+0\"
\n" ); document.write( "\"x%28x%5E2-5%29+=+0\"
\n" ); document.write( "set each term (the \"x\" and the \"x^2-5\" to zero to get:
\n" ); document.write( "x^2-5 = 0
\n" ); document.write( "x^2 = 5
\n" ); document.write( "x = +-sqrt(5)
\n" ); document.write( ".
\n" ); document.write( "and, of course
\n" ); document.write( "x = 0
\n" ); document.write( ".
\n" ); document.write( "so, the solution set is:
\n" ); document.write( "x = {-sqrt(5), 0, sqrt(5)}\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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