![\"\"](\"/images/stars/stars-13.gif\")
You can put this solution on YOUR website!
-2y < -8
\n" ); document.write( "or:
\n" ); document.write( "1 + 2y < 3
\n" ); document.write( "-----
\n" ); document.write( "-2y < -8 becomes y > 4
\n" ); document.write( "you divide both sides of the equation by -2 to get:
\n" ); document.write( "y > 4
\n" ); document.write( "the division by a negative number changes the inequality sign.
\n" ); document.write( "-8 / -2 = +4
\n" ); document.write( "if y = 4 which is equal to 4, -2y = -8 which is equal to -8.
\n" ); document.write( "if y = 5 which is greater than 4, -2y = -10 which is less than -8
\n" ); document.write( "if y = 3 which is less than 4, 3, -2y = -6 which is greater than -8
\n" ); document.write( "this means -2y < -8 is true when y > 4 and false when y = 4 and when y < 4.
\n" ); document.write( "answer is -2y < -8 when y > 4.
\n" ); document.write( "-----
\n" ); document.write( "1 + 2y < 3 becomes 2y < 2 becomes y < 1
\n" ); document.write( "if y = 1 which is equal to 1, 1 + 2y = 3 which is equal to 3.
\n" ); document.write( "if y = 2 which is greater than 1, 1 + 2y = 1 + 4 = 5 which is greater than 3.
\n" ); document.write( "if y = 0 which is smaller than 1, 1 + 2y = 1 which is less than 3.
\n" ); document.write( "this means that 1 + 2y < 3 is true when y is less than 1 and false when y = 1 and when y > 1.
\n" ); document.write( "answer is 1 + 2y < 3 when y < 1.
\n" ); document.write( "-----
\n" ); document.write( "answer that satisfies both equations is:
\n" ); document.write( "y > 4 or y < 1.
\n" ); document.write( "-----
\n" ); document.write( "you had y > -4
\n" ); document.write( "check you answer out again.
\n" ); document.write( "you looked ok with y < 1
\n" ); document.write( "that y > -4 is suspect.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "