document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=481144>Question 481144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangular garden has an area of 90 sq feet. It's height is 8 feet more than its base. Find the measure of the base. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #329513 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=329513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A triangular garden has an area of 90 sq feet. It's height is 8 feet more than its base. Find the measure of the base.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Since:<BR>\n" );
document.write( "A = (1/2)bh<BR>\n" );
document.write( "where<BR>\n" );
document.write( "A is area<BR>\n" );
document.write( "b is base<BR>\n" );
document.write( "h is height<BR>\n" );
document.write( ".<BR>\n" );
document.write( "90 = (1/2)b(b+8)<BR>\n" );
document.write( "180 = b(b+8)<BR>\n" );
document.write( "180 = b^2+8b<BR>\n" );
document.write( "0 = b^2+8b-180<BR>\n" );
document.write( "0 = (b+18)(b-10)<BR>\n" );
document.write( "b = {-18, 10}<BR>\n" );
document.write( "throw out the negative solution leaving:<BR>\n" );
document.write( "b = 10 feet (length of base)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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