document.write( "Question 481153: Factor & check\r
\n" ); document.write( "\n" ); document.write( "x^3+8x^2+2x+16, 2bc+4b-5c-10
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Algebra.Com's Answer #329494 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "x^3+8x^2+2x+16 Note: x = -8 is a root, thus(x+8) one factor
\n" ); document.write( "Applying synthetic division: (x^3+8x^2+2x+16)/(x+8) = x^2 + 2
\n" ); document.write( "-8 1 8 2 16
\n" ); document.write( " -8 0 -16
\n" ); document.write( " 1 0 2 0
\n" ); document.write( "x^3+8x^2+2x+16 = (x+8)(x^2+2) = x^3 + 8x^2 + 2x + 16
\n" ); document.write( " F First terms x^3
\n" ); document.write( " O Outside terms 2x
\n" ); document.write( " I Inside term 8x^2
\n" ); document.write( " L Last terms 16
\n" ); document.write( "2bc+4b-5c-10 = 2b(c + 2) - 5(c + 2 = (2b-5)(c+2)
\n" ); document.write( " F First terms 2bc
\n" ); document.write( " O Outside terms 4b
\n" ); document.write( " I Inside term -5c
\n" ); document.write( " L Last terms -10
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