document.write( "Question 481128: The one-to-one function is defined by\r
\n" ); document.write( "\n" ); document.write( "f(x) = x/(8-9x)\r
\n" ); document.write( "\n" ); document.write( "Find f^-1, the inverse of f . Then, give the domain and range of f^-1 using interval notation.
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Algebra.Com's Answer #329473 by stanbon(75887)\"\" \"About 
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The one-to-one function is defined by
\n" ); document.write( "f(x) = x/(8-9x)
\n" ); document.write( "Find f^-1, the inverse of f .
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\n" ); document.write( "1st: Interchange x and y to get:
\n" ); document.write( "x = y/(8-9y)
\n" ); document.write( "2nd: Solve for \"y\":
\n" ); document.write( "8x-9xy = y
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\n" ); document.write( "y+9xy = 8x
\n" ); document.write( "y(9x+1) = 8x
\n" ); document.write( "f^-1(x) = 8x/(9x+1)
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\n" ); document.write( "Domain: All Real Numbers except x = -1/9
\n" ); document.write( "Range: All Real Numbers except y = 8/9
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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\n" ); document.write( "\n" ); document.write( "Then, give the domain and range of f^-1 using interval notation.
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